3.242 \(\int \frac{(a+b x^3)^3}{x^4} \, dx\)

Optimal. Leaf size=37 \[ 3 a^2 b \log (x)-\frac{a^3}{3 x^3}+a b^2 x^3+\frac{b^3 x^6}{6} \]

[Out]

-a^3/(3*x^3) + a*b^2*x^3 + (b^3*x^6)/6 + 3*a^2*b*Log[x]

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Rubi [A]  time = 0.0202246, antiderivative size = 37, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.154, Rules used = {266, 43} \[ 3 a^2 b \log (x)-\frac{a^3}{3 x^3}+a b^2 x^3+\frac{b^3 x^6}{6} \]

Antiderivative was successfully verified.

[In]

Int[(a + b*x^3)^3/x^4,x]

[Out]

-a^3/(3*x^3) + a*b^2*x^3 + (b^3*x^6)/6 + 3*a^2*b*Log[x]

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin{align*} \int \frac{\left (a+b x^3\right )^3}{x^4} \, dx &=\frac{1}{3} \operatorname{Subst}\left (\int \frac{(a+b x)^3}{x^2} \, dx,x,x^3\right )\\ &=\frac{1}{3} \operatorname{Subst}\left (\int \left (3 a b^2+\frac{a^3}{x^2}+\frac{3 a^2 b}{x}+b^3 x\right ) \, dx,x,x^3\right )\\ &=-\frac{a^3}{3 x^3}+a b^2 x^3+\frac{b^3 x^6}{6}+3 a^2 b \log (x)\\ \end{align*}

Mathematica [A]  time = 0.0042985, size = 37, normalized size = 1. \[ 3 a^2 b \log (x)-\frac{a^3}{3 x^3}+a b^2 x^3+\frac{b^3 x^6}{6} \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x^3)^3/x^4,x]

[Out]

-a^3/(3*x^3) + a*b^2*x^3 + (b^3*x^6)/6 + 3*a^2*b*Log[x]

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Maple [A]  time = 0.006, size = 34, normalized size = 0.9 \begin{align*} -{\frac{{a}^{3}}{3\,{x}^{3}}}+{x}^{3}a{b}^{2}+{\frac{{b}^{3}{x}^{6}}{6}}+3\,{a}^{2}b\ln \left ( x \right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^3+a)^3/x^4,x)

[Out]

-1/3*a^3/x^3+x^3*a*b^2+1/6*b^3*x^6+3*a^2*b*ln(x)

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Maxima [A]  time = 0.946854, size = 46, normalized size = 1.24 \begin{align*} \frac{1}{6} \, b^{3} x^{6} + a b^{2} x^{3} + a^{2} b \log \left (x^{3}\right ) - \frac{a^{3}}{3 \, x^{3}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)^3/x^4,x, algorithm="maxima")

[Out]

1/6*b^3*x^6 + a*b^2*x^3 + a^2*b*log(x^3) - 1/3*a^3/x^3

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Fricas [A]  time = 1.6092, size = 85, normalized size = 2.3 \begin{align*} \frac{b^{3} x^{9} + 6 \, a b^{2} x^{6} + 18 \, a^{2} b x^{3} \log \left (x\right ) - 2 \, a^{3}}{6 \, x^{3}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)^3/x^4,x, algorithm="fricas")

[Out]

1/6*(b^3*x^9 + 6*a*b^2*x^6 + 18*a^2*b*x^3*log(x) - 2*a^3)/x^3

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Sympy [A]  time = 0.397016, size = 34, normalized size = 0.92 \begin{align*} - \frac{a^{3}}{3 x^{3}} + 3 a^{2} b \log{\left (x \right )} + a b^{2} x^{3} + \frac{b^{3} x^{6}}{6} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x**3+a)**3/x**4,x)

[Out]

-a**3/(3*x**3) + 3*a**2*b*log(x) + a*b**2*x**3 + b**3*x**6/6

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Giac [A]  time = 1.11797, size = 59, normalized size = 1.59 \begin{align*} \frac{1}{6} \, b^{3} x^{6} + a b^{2} x^{3} + 3 \, a^{2} b \log \left ({\left | x \right |}\right ) - \frac{3 \, a^{2} b x^{3} + a^{3}}{3 \, x^{3}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)^3/x^4,x, algorithm="giac")

[Out]

1/6*b^3*x^6 + a*b^2*x^3 + 3*a^2*b*log(abs(x)) - 1/3*(3*a^2*b*x^3 + a^3)/x^3